Originally Posted by plumies
Does it have anything to do with the cut-off frequencies of those modes? I'm just shooting in the dark here.
well, for me yes. because i have the formula for lower cut off but not upper.
for TE11 the formula is
Fc = 1.84(Ce) / 2(pi)b
Ce is velocity of light in a dielectric medium. 3*10^8 same as air.
b is the radius of my can in meters.
so i do this
Fc= 1.84*3(10^8) / 2*3.14159265*.0389
well that gives me
184000000 / .244415908 which = 752815156.3xxxxxx Hz
my professor ended up with 2253000000 Hz or 2.253Ghz
How the heck am i off so much
im not in a physics class, this is for my wireless communications class.